2t^2-2t+1=0

Solution for 2t^2-2t+1=0 equation:

Simplifying
2t2 + -2t + 1 = 0

Reorder the terms:
1 + -2t + 2t2 = 0

Solving
1 + -2t + 2t2 = 0

Solving for variable 't'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
0.5 + -1t + t2 = 0

Move the constant term to the right:

Add '-0.5' to each side of the equation.
0.5 + -1t + -0.5 + t2 = 0 + -0.5

Reorder the terms:
0.5 + -0.5 + -1t + t2 = 0 + -0.5

Combine like terms: 0.5 + -0.5 = 0.0
0.0 + -1t + t2 = 0 + -0.5
-1t + t2 = 0 + -0.5

Combine like terms: 0 + -0.5 = -0.5
-1t + t2 = -0.5

The t term is -1t.  Take half its coefficient (-0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1t + 0.25 + t2 = -0.5 + 0.25

Reorder the terms:
0.25 + -1t + t2 = -0.5 + 0.25

Combine like terms: -0.5 + 0.25 = -0.25
0.25 + -1t + t2 = -0.25

Factor a perfect square on the left side:
(t + -0.5)(t + -0.5) = -0.25

Can't calculate square root of the right side.

The solution to this equation could not be determined.